Java for searching a user's dn from all the users in active directory

search a user's dn from all the users in active directory and user memberOf

import java.util.Hashtable;
import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.Attribute;
import javax.naming.directory.Attributes;
import javax.naming.directory.BasicAttribute;
import javax.naming.directory.BasicAttributes;
import javax.naming.directory.DirContext;
import javax.naming.directory.InitialDirContext;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
public class ADTest {
    public static void main(String[] args) {
        Hashtable<String, String> env = new Hashtable<String, String>();
        env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
        env.put(Context.PROVIDER_URL, "ldap://ad.example.com:389");
        env.put(Context.SECURITY_AUTHENTICATION, "simple");
        env.put(Context.SECURITY_PRINCIPAL, "cn=Administrator,cn=Users,dc=ad,dc=example,dc=com");
        env.put(Context.SECURITY_CREDENTIALS, "password");
        try {
            DirContext ctx = new InitialDirContext(env);
            SearchControls searchControls = new SearchControls();
            searchControls.setSearchScope(SearchControls.SUBTREE_SCOPE);
            String searchFilter = "(&(objectClass=user)(sAMAccountName=testuser))";
            String searchBase = "dc=ad,dc=example,dc=com";
            NamingEnumeration<SearchResult> results = ctx.search(searchBase, searchFilter, searchControls);
            SearchResult searchResult = null;
            if (results.hasMoreElements()) {
                searchResult = (SearchResult) results.nextElement();
                Attributes attrs = searchResult.getAttributes();
                Attribute attr = attrs.get("memberOf");
                for (int i = 0; i < attr.size(); i++) {
                    String groupDN = (String) attr.get(i);
                    System.out.println(groupDN);
                }
            }
            ctx.close();
        } catch (NamingException e) {
            e.printStackTrace();
        }
    }
}

Find the OS Version and Kernel on Linux

 Type the following command to find Linux kernel version: uname -r.

[oracle@testmachine1 Oracle]$ uname -r
3.10.0-1160.81.1.el7.x86_64

 

Type any one of the following command to find os name and version in Linux: cat /etc/os-release. ...

[oracle@testmachine Oracle]$ cat /etc/os-release
NAME="Red Hat Enterprise Linux Server"
VERSION="7.9 (Maipo)"
ID="rhel"
ID_LIKE="fedora"
VARIANT="Server"
VARIANT_ID="server"
VERSION_ID="7.9"
PRETTY_NAME="Red Hat Enterprise Linux"
ANSI_COLOR="0;31"
CPE_NAME="cpe:/o:redhat:enterprise_linux:7.9:GA:server"
HOME_URL="https://www.redhat.com/"
BUG_REPORT_URL="https://bugzilla.redhat.com/"

REDHAT_BUGZILLA_PRODUCT="Red Hat Enterprise Linux 7"
REDHAT_BUGZILLA_PRODUCT_VERSION=7.9
REDHAT_SUPPORT_PRODUCT="Red Hat Enterprise Linux"
REDHAT_SUPPORT_PRODUCT_VERSION="7.9"